\(\int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx\) [556]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 35, antiderivative size = 10 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \log (3-2 x) \]

[Out]

-1/2*ln(3-2*x)

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.057, Rules used = {1600, 31} \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \log (3-2 x) \]

[In]

Int[(243 + 162*x + 108*x^2 + 72*x^3 + 48*x^4 + 32*x^5)/(729 - 64*x^6),x]

[Out]

-1/2*Log[3 - 2*x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 1600

Int[(u_.)*(Px_)^(p_.)*(Qx_)^(q_.), x_Symbol] :> Int[u*PolynomialQuotient[Px, Qx, x]^p*Qx^(p + q), x] /; FreeQ[
q, x] && PolyQ[Px, x] && PolyQ[Qx, x] && EqQ[PolynomialRemainder[Px, Qx, x], 0] && IntegerQ[p] && LtQ[p*q, 0]

Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{3-2 x} \, dx \\ & = -\frac {1}{2} \log (3-2 x) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.00 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \log (3-2 x) \]

[In]

Integrate[(243 + 162*x + 108*x^2 + 72*x^3 + 48*x^4 + 32*x^5)/(729 - 64*x^6),x]

[Out]

-1/2*Log[3 - 2*x]

Maple [A] (verified)

Time = 1.54 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.70

method result size
parallelrisch \(-\frac {\ln \left (x -\frac {3}{2}\right )}{2}\) \(7\)
default \(-\frac {\ln \left (-3+2 x \right )}{2}\) \(9\)
norman \(-\frac {\ln \left (-3+2 x \right )}{2}\) \(9\)
risch \(-\frac {\ln \left (-3+2 x \right )}{2}\) \(9\)
meijerg \(-\frac {x \left (\ln \left (1-\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}\right )-\ln \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}\right )+\frac {\ln \left (1-\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}{2}-\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{6}\right )^{\frac {1}{6}}}{3-\left (x^{6}\right )^{\frac {1}{6}}}\right )-\frac {\ln \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}{2}-\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{6}\right )^{\frac {1}{6}}}{3+\left (x^{6}\right )^{\frac {1}{6}}}\right )\right )}{12 \left (x^{6}\right )^{\frac {1}{6}}}-\frac {\ln \left (1-\frac {64 x^{6}}{729}\right )}{12}-\frac {x^{5} \left (\ln \left (1-\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}\right )-\ln \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}\right )+\frac {\ln \left (1-\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}{2}+\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{6}\right )^{\frac {1}{6}}}{3-\left (x^{6}\right )^{\frac {1}{6}}}\right )-\frac {\ln \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{6}}}{3}+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}{2}+\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (x^{6}\right )^{\frac {1}{6}}}{3+\left (x^{6}\right )^{\frac {1}{6}}}\right )\right )}{12 \left (x^{6}\right )^{\frac {5}{6}}}-\frac {x^{4} \left (\ln \left (1-\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )-\frac {\ln \left (1+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}+\frac {16 \left (x^{6}\right )^{\frac {2}{3}}}{81}\right )}{2}+\sqrt {3}\, \arctan \left (\frac {2 \sqrt {3}\, \left (x^{6}\right )^{\frac {1}{3}}}{9 \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}\right )\right )}{12 \left (x^{6}\right )^{\frac {2}{3}}}+\frac {\operatorname {arctanh}\left (\frac {8 x^{3}}{27}\right )}{6}-\frac {x^{2} \left (\ln \left (1-\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )-\frac {\ln \left (1+\frac {4 \left (x^{6}\right )^{\frac {1}{3}}}{9}+\frac {16 \left (x^{6}\right )^{\frac {2}{3}}}{81}\right )}{2}-\sqrt {3}\, \arctan \left (\frac {2 \sqrt {3}\, \left (x^{6}\right )^{\frac {1}{3}}}{9 \left (1+\frac {2 \left (x^{6}\right )^{\frac {1}{3}}}{9}\right )}\right )\right )}{12 \left (x^{6}\right )^{\frac {1}{3}}}\) \(399\)

[In]

int((32*x^5+48*x^4+72*x^3+108*x^2+162*x+243)/(-64*x^6+729),x,method=_RETURNVERBOSE)

[Out]

-1/2*ln(x-3/2)

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \, \log \left (2 \, x - 3\right ) \]

[In]

integrate((32*x^5+48*x^4+72*x^3+108*x^2+162*x+243)/(-64*x^6+729),x, algorithm="fricas")

[Out]

-1/2*log(2*x - 3)

Sympy [A] (verification not implemented)

Time = 0.02 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=- \frac {\log {\left (2 x - 3 \right )}}{2} \]

[In]

integrate((32*x**5+48*x**4+72*x**3+108*x**2+162*x+243)/(-64*x**6+729),x)

[Out]

-log(2*x - 3)/2

Maxima [A] (verification not implemented)

none

Time = 0.20 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.80 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \, \log \left (2 \, x - 3\right ) \]

[In]

integrate((32*x^5+48*x^4+72*x^3+108*x^2+162*x+243)/(-64*x^6+729),x, algorithm="maxima")

[Out]

-1/2*log(2*x - 3)

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.90 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {1}{2} \, \log \left ({\left | 2 \, x - 3 \right |}\right ) \]

[In]

integrate((32*x^5+48*x^4+72*x^3+108*x^2+162*x+243)/(-64*x^6+729),x, algorithm="giac")

[Out]

-1/2*log(abs(2*x - 3))

Mupad [B] (verification not implemented)

Time = 8.89 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.60 \[ \int \frac {243+162 x+108 x^2+72 x^3+48 x^4+32 x^5}{729-64 x^6} \, dx=-\frac {\ln \left (x-\frac {3}{2}\right )}{2} \]

[In]

int(-(162*x + 108*x^2 + 72*x^3 + 48*x^4 + 32*x^5 + 243)/(64*x^6 - 729),x)

[Out]

-log(x - 3/2)/2